40k^2-110k+70=0

Solution for 40k^2-110k+70=0 equation:

40k^2-110k+70=0

a = 40; b = -110; c = +70;
Δ = b2-4ac
Δ = -1102-4·40·70
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110)-30}{2*40}=\frac{80}{80}
=1
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110)+30}{2*40}=\frac{140}{80}
=1+3/4
$